wwe 2013 game

Divides a string into n strings each with a string length of MSample Input12 5//N mKlmbbileaySample OutputKlmbbIleay1# include 2# include 3# include 4# include 5# include string>6# include 7# include 8# include 9# define LLLong LongTen using namespacestd; One A Chars[ -] ; - - intMain () the { - //freopen ("In.txt", "R", stdin); - intT; -scanf"%d", T); + while(t--) - { + intN, M; Ascanf"%d%d", n,m); at intI, J; - intCNT =0 ; -scanf"%s", s); - f

number of operations required for building.Example 1 input 152 3 4 1 2Sample output 15PromptOne of the feasible best solutions is to select[] [] [] [] []For 30% of data, 1 ≤ n ≤ 10;For 70% of data, 1 ≤ n ≤ 1000;For 100% of data, 1 ≤ n ≤ 100000,0 ≤ Hi ≤ 10000.Solution:I wanted to write it with rmq, but it's a pity that it's down,After reading the problem on the internet, I went through greedy O (N). I ......Find the minimum value of the entire segment, and then find a bunch of non-decreasing int

Question: A 2x2 cube is provided, and a limited step length is given. Up to this length can be used to successfully spell Several faces. Purely simulate the question, clarify the transformation relationships of several faces, simplify the steps, three rotation methods, and two rotation directions. Both BFS and DFS can be used. # Include 2013 Changsha field game K (pocket cube)

[unit]" where number is a positive integer within [1, +] and unit is the description of size which could are "B", "KB", "MB", "GB", "TB", "PB", "EB", "ZB", "YB" in short respectively.Output for each test case, output one line ' case #x: Y ', where x is the ' Case number ' (starting from 1) and Y-is the Percen Tage of the "missing part". The answer should is rounded to both digits after the decimal point.Sample Input2100[MB]1[B]Sample OutputCase #1:4.63%case #2:0.00%HintSource2013 Asia Chengdu Re

if(judge (p,v)) + { -printf"0.0000\n"); $ Continue; $ } - DoubleV =V.len (); - DoubleD = Get_dis (v,p);//get the distance from the movement of the coin to the Origin . the //printf ("%.3lf\n", D); - DoubleAns =0;Wuyi if(D //would collide, pits, in which case the reflection of the subject was contrary to common sense, and has been WA here the { - DoubleL = sqrt ((r+r) * (r+r)-d*d+eps)-sqrt ((rm+r) * (rm+r)-d*